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# [Miscellaneous: Flipping bits](https://www.hackerrank.com/challenges/flipping-bits)

- Difficulty: `#easy`
- Category: `#ProblemSolvingBasic` `#BitManipulation`

## Using bitwise operations

The bitwise NOT operator (~) flips all bits of the number.

The & 0xFFFFFFFF ensures that we only keep the last 32 bits,
effectively simulating a 32-bit unsigned integer.

This is a more efficient and concise way to achieve the same result
as the original code, without needing to convert to binary strings.
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/**
* @link Problem definition [[docs/hackerrank/interview_preparation_kit/miscellaneous/flipping-bits.md]]
* @see Solution notes [[docs/hackerrank/interview_preparation_kit/miscellaneous/flipping-bits-alt-solution-notes.md]]
*/

function flippingBitsAlt(n) {
// eslint-disable-next-line no-bitwise
return ~n >>> 0;
}

export default { flippingBitsAlt };
export { flippingBitsAlt };
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import { describe, expect, it } from '@jest/globals';
import { logger as console } from '../../../logger.js';

import { flippingBitsAlt } from './flipping-bits-alt.js';

import TEST_CASES from './flipping-bits.testcases.json';

describe('flipping bits', () => {
it('flipping bits test cases', () => {
expect.assertions(10);

let totalTestsCount = 0;

TEST_CASES.forEach((testSet) => {
testSet.tests.forEach((test) => {
const answer = flippingBitsAlt(test.input);

console.debug(
`flippingBitsAlt(${test.input}) solution found: ${answer}`
);

expect(answer).toStrictEqual(test.expected);

totalTestsCount += 1;
});
});

expect(TEST_CASES).toHaveLength(3);
expect(totalTestsCount).toBe(8);
});
});