Create 2501. Longest Square Streak in an Array

2501. Longest Square Streak in an Array

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+class Solution {
+public:
+    int longestSquareStreak(vector<int>& nums) {
+        int longestStreak = -1,n;
+        n = nums.size();
+        vector<int> presenceChecker(100001,0);
+
+        // Keeping track of presence of each element of nums array in presenceChecker array.
+        for(int i=0;i<n;i++)
+            presenceChecker[nums[i]] = 1;
+
+        // Applying our algorithm for each element in nums array.
+        for(int i=0;i<n;i++){
+            long long int curr = nums[i];
+            int currLongestStreak = 1;
+            while(true){
+                if(curr*curr<100001 && presenceChecker[curr*curr] == 1){
+                    currLongestStreak++;
+                    curr = curr*curr;
+                }
+                else
+                    break;
+            }
+            // if there is atleat 1 next square present in the array then currLongestStreak will
+            // be always greater than 1.
+            if(currLongestStreak != 1)
+                longestStreak = max(longestStreak,currLongestStreak);
+        }
+
+        return longestStreak;
+    }
+};