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Original file line number Diff line number Diff line change
@@ -0,0 +1,42 @@
# [1375.Number of Times Binary String Is Prefix-Aligned][title]

## Description
You have a **1-indexed** binary string of length `n` where all the bits are `0` initially. We will flip all the bits of this binary string (i.e., change them from `0` to `1`) one by one. You are given a **1-indexed** integer array `flips` where `flips[i]` indicates that the bit at index `i` will be flipped in the `ith` step.

A binary string is **prefix-aligned** if, after the `ith` step, all the bits in the **inclusive** range `[1, i]` are ones and all the other bits are zeros.

Return the number of times the binary string is **prefix-aligned** during the flipping process.

**Example 1:**

```
Input: flips = [3,2,4,1,5]
Output: 2
Explanation: The binary string is initially "00000".
After applying step 1: The string becomes "00100", which is not prefix-aligned.
After applying step 2: The string becomes "01100", which is not prefix-aligned.
After applying step 3: The string becomes "01110", which is not prefix-aligned.
After applying step 4: The string becomes "11110", which is prefix-aligned.
After applying step 5: The string becomes "11111", which is prefix-aligned.
We can see that the string was prefix-aligned 2 times, so we return 2.
```

**Example 2:**

```
Input: flips = [4,1,2,3]
Output: 1
Explanation: The binary string is initially "0000".
After applying step 1: The string becomes "0001", which is not prefix-aligned.
After applying step 2: The string becomes "1001", which is not prefix-aligned.
After applying step 3: The string becomes "1101", which is not prefix-aligned.
After applying step 4: The string becomes "1111", which is prefix-aligned.
We can see that the string was prefix-aligned 1 time, so we return 1.
```

## 结语

如果你同我一样热爱数据结构、算法、LeetCode,可以关注我 GitHub 上的 LeetCode 题解:[awesome-golang-algorithm][me]

[title]: https://leetcode.com/problems/number-of-times-binary-string-is-prefix-aligned
[me]: https://github.com/kylesliu/awesome-golang-algorithm
Original file line number Diff line number Diff line change
@@ -1,5 +1,14 @@
package Solution

func Solution(x bool) bool {
return x
func Solution(flips []int) int {
ans := 0
sum, cur := 0, 0
for i, f := range flips {
sum += i + 1
cur += f
if sum == cur {
ans++
}
}
return ans
}
Original file line number Diff line number Diff line change
Expand Up @@ -10,12 +10,11 @@ func TestSolution(t *testing.T) {
// 测试用例
cases := []struct {
name string
inputs bool
expect bool
inputs []int
expect int
}{
{"TestCase", true, true},
{"TestCase", true, true},
{"TestCase", false, false},
{"TestCase1", []int{3, 2, 4, 1, 5}, 2},
{"TestCase2", []int{4, 1, 2, 3}, 1},
}

// 开始测试
Expand All @@ -30,10 +29,10 @@ func TestSolution(t *testing.T) {
}
}

// 压力测试
// 压力测试
func BenchmarkSolution(b *testing.B) {
}

// 使用案列
// 使用案列
func ExampleSolution() {
}
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