Solving day 11 #12
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Solving day 11 #12
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* Decrease loops and complexity
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Summary
Solution for day 11's puzzle. This solution does not store the number on each stone, but rather the base10 digits. In this way, we avoid cases of integer overflow, and make the act of splitting the digits into two stones very easy. The difficult is multiplying, which is done like a grade school student - long form multiplication. The first implementation was a little sloppy, so a second commit was made that cleans up the implementation.