Simplify doc-cfg rendering based on the current context

For sub-items on a page don't show cfg that has already been rendered on
a parent item. At its simplest this means not showing anything that is
shown in the portability message at the top of the page, but also for
things like fields of an enum variant if that variant itself is
cfg-gated then don't repeat those cfg on each field of the variant.

This does not touch trait implementation rendering, as that is more
complex and there are existing issues around how it deals with doc-cfg
that need to be fixed first.

Author: Nemo157

src/librustdoc/clean/cfg.rs

@@ -201,6 +201,35 @@ impl Cfg {
             _ => false,
         }
     }
+
+    /// Attempt to simplify this cfg by assuming that `assume` is already known to be true, will
+    /// return `None` if simplification managed to completely eliminate any requirements from this
+    /// `Cfg`.
+    pub(crate) fn simplify_with(&self, assume: &Cfg) -> Option<Cfg> {
+        if self == assume {
+            return None;
+        }
+
+        if let Cfg::All(a) = self {
+            let mut sub_cfgs: Vec<Cfg> = if let Cfg::All(b) = assume {
+                a.iter().filter(|a| !b.contains(a)).cloned().collect()
+            } else {
+                a.iter().filter(|&a| a != assume).cloned().collect()
+            };
+            let len = sub_cfgs.len();
+            return match len {
+                0 => None,
+                1 => sub_cfgs.pop(),
+                _ => Some(Cfg::All(sub_cfgs)),
+            };
+        } else if let Cfg::All(b) = assume {
+            if b.contains(self) {
+                return None;
+            }
+        }
+
+        Some(self.clone())
+    }
 }
 
 impl ops::Not for Cfg {